<?xml version="1.0" encoding="utf-8" standalone="yes"?><rss version="2.0" xmlns:atom="http://www.w3.org/2005/Atom"><channel><title>Marios Rozos | LIP6 - Équipe QI</title><link>https://qi.lip6.fr/fr/people/marios-rozos/</link><atom:link href="https://qi.lip6.fr/fr/people/marios-rozos/index.xml" rel="self" type="application/rss+xml"/><description>Marios Rozos</description><generator>Hugo Blox Builder (https://hugoblox.com)</generator><language>fr</language><copyright>© 2022 LIP6 Quantum Information Team</copyright><lastBuildDate>Wed, 13 May 2026 00:00:00 +0000</lastBuildDate><image><url>https://qi.lip6.fr/media/icon_hu_bdeccd9e706ea09d.png</url><title>Marios Rozos</title><link>https://qi.lip6.fr/fr/people/marios-rozos/</link></image><item><title>The Complexity of Stoquastic Sparse Hamiltonians</title><link>https://qi.lip6.fr/fr/publication/5621723-the-complexity-of-stoquastic-sparse-hamiltonians/</link><pubDate>Wed, 13 May 2026 00:00:00 +0000</pubDate><guid>https://qi.lip6.fr/fr/publication/5621723-the-complexity-of-stoquastic-sparse-hamiltonians/</guid><description>&lt;p&gt;Despite having an unnatural definition, $\mathsf{StoqMA}$ plays a central role in Hamiltonian complexity, e.g., in the classification theorem of the complexity of Hamiltonians by Cubitt and Montanaro (SICOMP 2016). Moreover, it lies between the two randomized extensions of $\mathsf{NP}$, $\mathsf{MA}$ and $\mathsf{AM}$. Therefore, understanding the exact power of $\mathsf{StoqMA}$ (and hopefully collapsing it with more natural complexity classes) is of great interest for different reasons. In this work, we take a step further in understanding this complexity class by showing that the Stoquastic Sparse Hamiltonians problem ($\mathsf{StoqSH}$) is in $\mathsf{StoqMA}$. Since Stoquastic Local Hamiltonians are $\mathsf{StoqMA}$-hard, this implies that $\mathsf{StoqSH}$ is $\mathsf{StoqMA}$-complete. We complement this result by showing that the separable version of $\mathsf{StoqSH}$ is $\mathsf{StoqMA}(2)$-complete, where $\mathsf{StoqMA}(2)$ is the version of $\mathsf{StoqMA}$ that receives two unentangled proofs.&lt;/p&gt;</description></item></channel></rss>